Given two words word1 and word2, find the minimum number of operations required to convert word1 to word2.
You have the following 3 operations permitted on a word:
- Insert a character
- Delete a character
- Replace a character
Example 1:
Input: word1 = "horse", word2 = "ros" Output: 3 Explanation: horse -> rorse (replace 'h' with 'r') rorse -> rose (remove 'r') rose -> ros (remove 'e')
Example 2:
Input: word1 = "intention", word2 = "execution" Output: 5 Explanation: intention -> inention (remove 't') inention -> enention (replace 'i' with 'e') enention -> exention (replace 'n' with 'x') exention -> exection (replace 'n' with 'c') exection -> execution (insert 'u')
// 31/05/2020
int minDistance(string word1, string word2) {
auto size1 = word1.size();
auto size2 = word2.size();
vector<vector<int>> mindist(size2+1, vector<int>(size1+1, 0));
for(int i = 1; i < size1 + 1; ++i)
mindist[0][i] = i;
for(int j = 1; j < size2 + 1; ++j)
mindist[j][0] = j;
for(int j = 1; j < size2 +1; ++j){
for(int i = 1; i < size1 + 1; ++i){
mindist[j][i] = (word1[i-1] == word2[j-1])?
mindist[j-1][i-1]
:1 + min({mindist[j-1][i],
mindist[j][i-1],
mindist[j-1][i-1]});
}
}
return mindist[size2][size1];
}