-
Notifications
You must be signed in to change notification settings - Fork 1
/
Copy pathbinary-tree-postorder-traversal.js
70 lines (60 loc) · 1.27 KB
/
binary-tree-postorder-traversal.js
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
/**
* Source: https://leetcode.com/problems/binary-tree-postorder-traversal/
* Tags: [Tree,Stack]
* Level: Hard
* Title: Binary Tree Postorder Traversal
* Auther: @imcoddy
* Content: Given a binary tree, return the postorder traversal of its nodes' values.
*
*
* For example:
* Given binary tree {1,#,2,3},
*
* 1
* \
* 2
* /
* 3
*
*
*
* return [3,2,1].
*
*
* Note: Recursive solution is trivial, could you do it iteratively?
*/
/**
* Definition for binary tree
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @returns {number[]}
*/
//TODO Add iterative solution
var postorderTraversal = function(root) {
function recursiveTraversal(root, result) {
if (!root) {
return [];
}
recursiveTraversal(root.left, result);
recursiveTraversal(root.right, result);
result.push(root.val);
return result;
}
return recursiveTraversal(root, []);
};
function TreeNode(val) {
this.val = val;
this.left = this.right = null;
}
var node = new TreeNode(1);
var root = node;
node = new TreeNode(2);
root.right = node;
node = new TreeNode(3);
root.left = node;
console.log(postorderTraversal(root));