020_Even or Odd in Array.py

"""
Codewars Coding Challenge

Odd or Even?

Given a list of integers, determine whether the sum of its elements is odd or even.

Give your answer as a string matching "odd" or "even".

If the input array is empty consider it as: [0] (array with a zero).

Examples:
Input: [0]
Output: "even"

Input: [0, 1, 4]
Output: "odd"

Input: [0, -1, -5]
Output: "even"
Have fun!

https://www.codewars.com/kata/5949481f86420f59480000e7/train/python
"""


# My Solution
def odd_or_even(arr):
    if sum(arr) % 2 == 0:
        return "even"
    else:
        return "odd"




# Sample test
"""
import codewars_test as test
from solution import odd_or_even

@test.describe("Fixed Tests")
def fixed_tests():
    @test.it('Basic Test Cases')
    def basic_test_cases():
        test.assert_equals(odd_or_even([0, 1, 2]), "odd")
        test.assert_equals(odd_or_even([0, 1, 3]), "even")
        test.assert_equals(odd_or_even([1023, 1, 2]), "even")

"""


"""
PERFECT SOLUTION FROM CODEWARS

=1=
def oddOrEven(arr):
    return 'even' if sum(arr) % 2 == 0 else 'odd'


=2=
def oddOrEven(arr):
    return ('even', 'odd')[sum(arr) % 2]


=3=
oddOrEven = lambda l: "odd" if sum(l) % 2 else "even"

"""