Count the number of occurrences of each character and return it as a (list of tuples) in order of appearance. For empty output return (an empty list).
Consult the solution set-up for the exact data structure implementation depending on your language.
Example:
orderedCount("abracadabra") == [['a', 5], ['b', 2], ['r', 2], ['c', 1], ['d', 1]]